Question

x pe radical din 20 = - radical din 232 pe 10= 3 radical 80 pe 10​

Answer 1

x/V20 - V320/10 = 3V80/10

V20 = 2V5

V320= 8V5

V80= 4V5

x/2V5 = (3×4V5)/10 + 8V5/10

x/2V5 = (12V5+8V5)/10

x/2V5 = 20V5/10

x/2V5 = 2V5

x= 2V5 ×2V5

x= 4×5

x=20

Answer 2

$\it \dfrac{^{\sqrt{20})}x}{\ \ \ \sqrt{20}}- \dfrac{\sqrt{320}}{10}=\dfrac{3\sqrt{80}}{10} \Rightarrow \dfrac{x\sqrt20}{20}= \dfrac{3\sqrt{16\cdot5}}{10}+ \dfrac{\sqrt{64\cdot5}}{10}|_{\cdot10} \Rightarrow\\ \\ \\ \Rightarrow \dfrac{x\sqrt{20}}{2}=12\sqrt5+8\sqrt5 \Rightarrow \dfrac{x\cdot2\sqrt5}{2}=20\sqrt5 \Rightarrow x\sqrt5=20\sqrt5 \Rightarrow x=20$