Question

x supra x^2 -36 =2supra x+6 + 1supra x-6 .
Mersi anticipat.

Answer 1

[tex] \frac{x}{ x^{2} -36}= \frac{2}{x+6}+ \frac{1}{x-6} \\ \frac{x}{ (x-6)(x+6)}- \frac{2}{x+6}- \frac{1}{x-6}=0 \\ \frac{x-2(x-6)-(x+6)}{(x-6)(x+6)}=0 \\ \frac{x-2x+12-x-6}{(x-6)(x+6)} =0 \\ \frac{6-2x}{(x-6)(x+6)}=0 [/tex]
DVA: R\{-6, 6}
$6-2x=0 \\ -2x=-6 \\ x=3$
S={3}