Question

| x(x-2) -(x-3)^3 |=3

|(2- x) (x+2)+(x+3)^2 |=5

|4x^2 +9x -9|=0

|(x+1)^3 - (x-2)^3|=9

Answer 1

|2x+ 4 -x^2 -2x + x^2+ 6x+9|=5
|6x+13|=5
6x+13=5 ⇒ 6x= 5 - 13 = - 8 ⇒ x= - 8/6 = -  4/3
6x+13= - 5⇒ 6x= -5 - 13 = -18⇒ x= -18:6= - 3

trebuie sa rezolv ec de gr 2
Δ=9^2 - 4 *9* (-9)= 81 + 324= 405
√Δ=√5*81=9V5
x1= ( -9 + 9√5)/8
x2= ( -9 - 9√5)/8

| x^3+1+3x^2+3x+x^3+8+3*x^2*(-2)+3x(-2)^2 |=              |2x^3 - 3x^2+15x +9| = 9
2x^3-3x^2+15x+9=9
2x^3-3x^2+15x=0
x(2x^2-3x+15)=0
x1=0
Δ=9-4*2*15 ⇒ Δ<0 ⇒ ec de gr 2 nu are solutie