Question

x+y+z=34;x/3=y/5=z/9.Aflati x,y,z

Answer 1

x/3=y/5=z/9=k
x/3=k=>x=3k
y/5=k=>y=5k
z/9=k=>z=9k
3k+5k+9k=34
20k=34
k=34/20(simplificam cu 2)
k=17/10


SPER CA TE-AM AJUTAT!!=>>>

Answer 2

x+y+z=34

X/3=y/5=z/9, x,y,z=?

x/3=y/5=z/9=K

x/3=>x=3K

y/5=>y=5K

z/9=>z=9K

3K+5K+9K=34

8K+9K=34

17K=34

K=34÷17

K=2

x=3k

x=3×2

x=6

y=5K

y=5×2

y=10

z=9K

z=9×2

z=18

V:6+10+18=16+18=34

Sper ca te am ajutat ;)