Question

x+y+z=51
2x+3y+4z=195
_______________
(2x+y)*(2z+y)*(z-x)=?

Answer 1

x+y+z=51   (1) ⇒ x+y=51-z⇒ 2x+2y=2(51-z)=102-2z
2x+3y+4z=195 ⇒ 102-2z+y+4z=195⇒ 102+y+2z=195⇒ y+2z=93⇒ y=93-2z
inlocuiesc in (1) x + 93 - 2z + z = 51 ⇒ x + 93 - z= 51⇒ x =51 +z - 93 = z - 42
2x+y=2(z-42)+93-2z=2z-84+93-2z=9
2z+y=2z+93-2z=93
z-x=z-z+42=42
⇒ (2x+y)(2z+y)(z-x)=9*93*42=35154