Question

x²+6-3≥x²+2x+9 ajutor pls

Answer 1

$x^2+6x-3\geq x^{2} +2x+9\\x^{2} +6x-3-x^{2} -2x-9\geq 0\\4x-12\geq 0\\4x\geq 12\\x\geq 12/4\\x\geq 3\\x=[3,inf)$