Question

xla2=1+3+5+...+101. rezolvati ecuatia va rogg

Answer 1

o suma de numere impare este egala cu nr de termeni la patrat => x²=51²=> x=51

Answer 2

   
[tex]\displaystyle \\ x^2 = 1+3+5+ \hdots +101 \\ \texttt{Calculam numarul termenilor sumei (n)}. \\ \\ n= \frac{101-1}{2}+1 = \frac{100}{2}+1 = 50 + 1 = 51~de ~termeni \\ \\ x^2 = \frac{51(101+1)}{2} \\ \\ x^2 = \frac{51 \times 102}{2} \\ \\ x^2 = 51 \times 51 \\ \\ x^2 = 51 ^2 \\ \\ x = \sqrt{51^2} = \boxed{51} [/tex]