Question

z=2(1-3i)^2 aflati |z|

Answer 1

Răspuns

Explicație pas cu pas:

$z=2(1-3i)^2=2(1-6i-9)=2(-8-6i)=-16-12i\\|z|=\sqrt{(-16)^2+(-12)^2}=\sqrt{256+144}=\sqrt{400}=\bold{\boxed{20}}$

Answer 2

z = 2(1-3i)² = 2(1-6i+9i²) = 2(1-6i-9) = 2(-6i-8) = -12i-16 (stim ca i²=-1)

|z| = √(a²+b²) = √(144+256) = √400 = 20