Question

1+2²×(3²÷3²-1)÷2³+2004⁰​

Answer 1

Răspuns: $\bf \red{\underline{~2~}}$

Explicație pas cu pas:

$\bf 1+2^2\cdot (3^2:3^2-1):2^3+2004^0=$

$\bf 1+2^2\cdot (3^{2-2}-1):2^3+1=$

$\bf 1+2^2\cdot (3^{0}-1):2^3+1=$

$\bf 1+2^2\cdot (1-1):2^3+1=$

$\bf 1+2^2\cdot 0:2^3+1=$

$\bf 1+0:2^3+1=$

$\bf 1+0+1=\red{\underline{2}}$

==pav38==

Answer 2

$\it = 1+4\cdot(1-1):8+1=1+1=2$