Question

1) In cursul arderilor din organism, glucoza elibereaza o cantitate de energie de 2817 Kj/mol. calculati cantitatea de energie eliberata de 50 g de ciocolata cu 80% glucoza.

Answer 1

80% din 50 g = 1,6 g glucoza

1 mol... 180g glucoza ... 2817 Kj
 ............ 1,6 g glucoza.....x Kj

x=1,6 * 2817 / 180 = 25, 04 Kj

Answer 2

0.8*50=40g C6H12O6

n=m/M=40/180=0.222 moli C6H12O6

1mol..............................2817 kj/mol
0.222mol...................x=625.99=626 kj/mol

MC6H12O6=180g/mol