Question

1) In triunghiul ABC cu m=(<A)=90°, [AD] inaltime, AD=√6 si BD=3•DC. Aflati BC. 

Answer 1

Teorema inaltimii in ΔABC: AD²=BD·DC=3DC² ⇒ DC=√2 cm; BD=3DC=3√2 cm;
BC=BD+DC=4√2 cm.

Answer 2

din T. Inalt ----> AD[tex] AD^{2} = BD*DC ------> 6=3DC*DC DC= \sqrt{2} -----[/tex]
BD=3$\sqrt{2}$ -------> BD= 4$\sqrt{2}$