Question

104-64:{13-12:[22-5x(38-4xA)]+4}=100
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Answer 1

64:{13-12:[22-5x(38-4xa)]+4}=104-100
64:{13-12:[22-5x(38-4xa)]+4}=4
{13-12:[22-5x(38-4xa)]+4}=64:4
{13-12:[22-5x(38-4xa)]+4}=16
{13-12:[22-5x(38-4xa)]=16-4
13-12:[22-5x(38-4xa)]=12
12:[22-5x(38-4xa)=13-12
12:[22-5x(38-4xa)=1
22-5x(38-4xa)=12:1
5x(38-4xa)=22-12
5x(38-4xa)=10
38-4xa=10:5
38-4xa=2
4xa=38-2
4xa=36
a=36:4
a=9
104-64:{13-12:[22-5x(38-4x9)]+4}=100
                                                 100=100