Question

12supra91x[1supra3+1:(1supra7+6supra7x1supra6):7supra6]+6supra13x[1supra4+(7supra36-1supra24):7supra6

Answer 1

12/91 · [1/3+1:(1/7+6/7 · 1/6) : 7/6] + 6/13 · [1/4 + (7/36 - 1/24) :7/6]= (am presupus unde se inchide a doua paranteza dreapta)
=12/91 · [1/3 +(1/7 +1/7) : 7/6] + 6/13 · [1/4+ (14/72-3/72) :7/6]=
=12/91 · [1/3 + 2/7·6/7] + 6/13 · [1/4 + 11/72 · 6/7]=
= 12/91 · [1/3 +12/14] + 6/13 · [1/4 + 11/12 · 1/7]=
=12/91 · (14/42 + 36/42) + 6/13 · (21/84 + 11/84]=
= 12/91· 50/42 + 6/13 ·32/84=
= 12/91·25/21 + 6/13·8/21=
= 12·25/7·13·3·7 + 6·8/13·3·7=
=300/3·637 + 48·7/3·637=
=100/637+16·7/637=
=100/637 + 112/637=
=212/637
urat a dat... sper sa nu fi gresit