Question

(18*3^4)^2: (3^12 + 3^13)
Ajutati-ma va rog! Vreau rezolvarea completa si explicatii daca se poate. P.s. daca nu stiti "^" inseamna ridicat la putere.

Answer 1

$\frac{(18*3^{4})^{2}}{3^{12}+3^{13}}=\frac{(2*3^{2}*3^{4})^{2}}{3^{12}*(1+3)}=\frac{(2*3^{2+4})^{2}}{3^{12}*4}=\frac{(2*3^{6})^{2}}{3^{12}*4}=\frac{2^{2}*3^{6*2}}{3^{12}*4}=\frac{4*3^{12}}{3^{12}*4}=1$