Question

Calculați (608÷16-270÷30)×2-19×3. 2583÷[2+5(72÷9+121÷11)-7×8]. [(205÷5+13×5)÷2-2×25]÷3+1
25-[300÷10+2(725÷5-29×)-4-5]
3×[35+16×(230-19×12)]-[14×3+82×3-4×(2+4×5)]
[302+19×(68-8×6)]÷2-2×17×10
25×13+325÷[278-17×(27-7-18×10)]

Answer 1

(608:16-270:30)x2-19x3=(38-9)x2-57=29x2-57=1

2583:[2+5(72:9+121:11)-7x8]=2583:[2+5(8+11)-56]=2583:(2+5x19-56)=2583:(2+95--56)=2583.41=63

[(205:5+13x5):2-2x25]:3+1=[(41+65):2-50]:3+1=(106:2-50):3+1=(53-50):3+1=1+1=2

25-[300:10+2(725:5-29x?????nu ceva lipseste

3x[35+16x(230-19x12)]-[14x3+82x3-4x(2+4x5)]=3x[+16(230-288)]-[42+246-4(2+20)]=3(35+16x2)-(288-4x22)=3x(35+32)-(288-88)=3x67-200=201-200=1

[302+19(68-8x6)]2-2x17x10=[302+19(68-48)]:2-340=(302+19x20):2-340=(302+380):2-340=682:2-340=341-340=1

în ultima paranteză ceva nu e corect scris   27-7-18........