Question

(-2)¹⁰¹÷2⁹⁹-10×{-3-3×[(-3)⁵÷3⁴-2]} dau coroana ​

Answer 1

Explicație pas cu pas:

${( - 2)}^{101} \div {2}^{99} - 10 \times \{ - 3 - 3 \times [ {( - 3)}^{5} \div {3}^{4} - 2] \} =$

$= { - 2}^{101} \div {2}^{99} - 10 \times \{ - 3 - 3 \times [ { - 3}^{5} \div {3}^{4} - 2] \}$

$= - {2}^{2} - 10 \times [ - 3 - 3 \times (- 3 - 2)]$

$= - 4 - 10 \times [ - 3 - 3 \times (- 5)]$

$= - 4 - 10 \times ( - 3 + 15)$

$= - 4 - 10 \times 12$

$= - 4 - 120$

$= - 124$