Question

2 la puterea n plus 3 minus 2 la puterea n plus 1.

Answer 1

Explicație pas cu pas:

${2}^{n + 3} - {2}^{n + 1} = {2}^{n + 1} \cdot ( {2}^{2} - 1) = {2}^{n + 1} \cdot (4 - 1) = 3 \cdot {2}^{n + 1}$

Answer 2

Răspuns:

^ =la puterea

2^n+3+2^n+1+2^n=88

2^n(2^3+2+1)=88

2^n · 11 = 88

2^n=8 = 2^3

n=3