Question

.....................20pct​

Answer 1

Explicație pas cu pas:

a)

$\frac{1}{1\cdot 2} + \frac{1}{2 \cdot 3} + \frac{1}{3 \cdot 4} + ... + \frac{1}{98 \cdot 99} + \frac{1}{99 \cdot 100} =$

$= \frac{1}{1} - \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + ... + \frac{1}{98} - \frac{1}{99} + \frac{1}{99} - \frac{1}{100}$

$= \frac{1}{1} - \frac{1}{100} = \frac{100 - 1}{100} = \frac{99}{100}$

→

$0,5 = \frac{50}{100} < \frac{99}{100} < \frac{100}{100} = 1$

b)

$\frac{2}{1\cdot 3} + \frac{2}{3 \cdot 5} + \frac{2}{5 \cdot 7} + ... + \frac{2}{97 \cdot 99} + \frac{2}{99 \cdot 101} =$

$= \frac{1}{1} - \frac{1}{3} + \frac{1}{3} - \frac{1}{5} + \frac{1}{5} - \frac{1}{7} + ... + \frac{1}{97} - \frac{1}{99} + \frac{1}{99} - \frac{1}{101}$

$= \frac{1}{1} - \frac{1}{101} = \frac{101 - 1}{101} = \frac{100}{101}$

→

$\frac{2}{5} = \frac{40}{100} < \frac{100}{101} < \frac{101}{101} = 1$

q.e.d.