Question

3.Rezolvati in R ecuatiile :
c)x²-12x+36=3
e)x²+10x=24
g) 25x²-10x-8=0
i)5 supra x-1=x-1 supra 45
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Trebuie sa aflu x1 si x2.... Va roooog

Answer 1

c) x² - 12x + 36-3=0
 x²-12x +33=0
Δ= -12² - 4 × 33 ×1 = 144- 132= 12
x 1,2 = 12 + sau - √Δ  supra 2 
 x1= 12 + 2√3 supra 2
x2= 12 - 2√3 supra 2 

e)  x²+10x=24 
 x²+ 10x -24=0
Δ= 10²- 4 ×(-24) × 1 = 100 + 96= 196 
x1,2 = -10 + sau - √Δ supra 2
x1= -10 + 14 supra 2 = 2
x2 = -10 - 14 supra 2 = - 1

Answer 2

C) (x-6)^2=3, x1=6+√3, x2=6-√3, E) (x+5)^2=49, x1=7-5=2, x2=-7-5=-12, I) aduci la numitor: (x-1)^2=225, (x-1)^2=15^2, x-1=15, x=16