Question

32 la puterea 25 - 4 la puterea 62 - 8 la puterea 41 = 2 la puterea x ori 4 la puterea x

afla x

Answer 1

(2^5)^25 - (2^2)^62 - (2^3)^41 = 2^x * 2^2x

2^125 - 2^124 - 2^123 = 2^3x

2^123 * (2^2 - 2 - 1) = 2^3x

Calculele din paranteza dau 4-2-1 = 1

2^123 = = 2^3x

3x = 123

X=41