Question

35 Scoateţi factorii de sub radical, apoi calculați rapoartele a A=6√8-3√32+9√50+5√18; B-7√486-4√150+11√24-3√96; C=3√108+2√192-4√12-2√75; CA=5√/28+2√343-4√/63-3√/112; B=2√56-2√126+√504-4√224; C=3√162+2√98-5√18-2√72; R A.B C şi A-C B : A=7√12 + 3√108-2√/243-2√/363; B=3√60+7√135-2√240-3√375; C = 2√245-3√20-√80+2√45; d-3√32-5√72-2√/200 + 3√/288 ; B= 2√250+3√40-2√490+3√360; C=√180+2√500-3√245-4√20.​.
Dau coroană

Answer 1

Răspuns:

A= 6√8-3√32+9√50+5√18=60√2

- Scoatem factorii de sub radical

1) 6√8= 12√2

2) 3√32= 12√2

3) 9√50= 45√2

4) 5√18= 15√2

deci continuăm:

A= 6√8-3√32+9√50+5√1= 12√2-12√2+45√2+15√2= 60√2