Question

(3radical din 2+2radical din 5)la adoua

Answer 1

$(3 \sqrt{2} +2 \sqrt{5} )^2=(3 \sqrt{2} )^2+2 \cdot 3 \sqrt{2} \cdot 2 \sqrt{5} +(2 \sqrt{5} )^2= \\ =18+12 \sqrt{10} +20=38+12 \sqrt{10}$

Answer 2

(3√2+2√5)²=
=3²√2²+2²√5²=
=9√4+4√25=
=18+20=
=38