Question

3x+5=-9
19-3(2x-1)=2
4(3x+8)+6(2x-3)+5=5(2x-3)+2x+30
ajutor pls

Answer 1

a)3x+5=-9

3x=-9-5=-14

$x = - \frac{14}{3}$

b)19-3(2x-1)=2

-3(2x-1)=2-19=-17

$2x - 1 = \frac{ - 17}{ - 3} = \frac{17}{3} \\ \\ 2x = \frac{17}{3} + 1 = \frac{20}{3} \\ \\ x = \frac{ \frac{20}{3} }{2} = \frac{20}{3 \times 2} = \frac{20}{6} = \frac{10}{3}$

c)4(3x+8)+6(2x-3)+5=5(2x-3)+2x+30

12x+32+12x-18+5=10x-15+2x+30

24x+19=10x-15+2x+30=12x+15

24x+19-12x=15

12x+19=15

12x=15-19=-4

$x = - \frac{4}{12} = - \frac{1}{3}$