Question

4.calculati compozitia procentuala din raportul de masa se masele moleculare pentru acidul azotic si sulfat de cupru

Answer 1

HNO3  = 1+14+16*3=63g/mol
%H=1/63*100=m hidrogen/masa molara acid * 100
%N=14/63*100=m azot/masa molara acid * 100
%O=48/63*100=m oxigen/masa molara acid * 100
raport masic = 1:1:3

CuSO4=64+32+4*16=160g/mol
%O=4*16/160*100
%Cu=64/160*100
%S=32/160*100