Question

5,6 ml de etan si propan (c.n) dau prin ardere 30,8 g CO2. Procentul volumetric de etan si amestec este ?

Answer 1

C2h6+ 7/2 o2->2 co2 + 3h2o C3h8+ 5o2-> 3co2+ 4h2o Amestec{ c2h6 xmoli { c3h8 ymoli C total {2x moli {3y moli 5.6/22.4=0.25 moli amestec X+y= 0.25=> y=0.25-x Mco2= 44 30.8/44=0.7 moli co2 2x+3y=0.7 2x+ 3(0.25-x)=0.7 2x+ 0.75- 3x=0.7 0.75- x=0.7 X=0.75-0.7=>x=0.05moli 0.25 moli amestec.........0.05moli c2h6 100 moli amestec..........a moli c2h6 =>a=20%. C2h6