Question

5 Efectuați: a 1 1 1 18 → b 7 36 1 3 + 18 4' C 37 3 5 18 4 6 d 2. 11 4 5 1 18 9 6 3​

Answer 1

$\displaystyle a)~\frac{1}{18} +\frac{^{2)}1}{9} +\frac{^{3)}1}{6} =\frac{1+2\cdot 1+3\cdot 1}{18} =\frac{1+2+3}{18}=\frac{6^{(6}}{18} =\frac{1}{3} \\\\b)~\frac{7}{36}-\frac{^{2)}1}{18} +\frac{^{9)}3}{4} = \frac{7-2\cdot1+9\cdot3}{36} =\frac{7-2+27}{36} =\frac{32^{(4}}{36} =\frac{8}{9} \\\\c)~\frac{^{2)}37}{18} -\frac{^{9)}3}{4}-\frac{^{6)}5}{6} =\frac{2\cdot37-9\cdot3-6\cdot5}{36} =\frac{74-27-30}{36}= \frac{17}{36}$

$\displaystyle d)~\frac{11}{18} -\frac{^{2)}4}{9} +\frac{^{3)}5}{6} -\frac{^{6)}1}{3}= \frac{11-2\cdot4+3\cdot5-6\cdot1}{18} =\frac{11-8+15-6}{18} =\\\\=\frac{12^{(6}}{18} =\frac{2}{3}$