Question

5 va rog dau coroana

Answer 1

Răspuns:

5.

a)

$( \sqrt{2} + x)^{2} = 2 + 2 \sqrt{2} x + {x}^{2}$

b)

$(x - \sqrt{5} )^{2} = {x}^{2} - 2 \sqrt{5} x + 5$

c)

$(y + 2 \sqrt{2} )^{2} = {y}^{2} + 4 \sqrt{2}y + 8$

d)

$( \sqrt{3} x - 1)^{2} = 3 {x}^{2} - 2 \sqrt{3} x + 1$

e)

$( \sqrt{2} a - 3)^{2} = 2 {a}^{2} - 6 \sqrt{2}a + 9$

f)

$(2x - \sqrt{3} )^{2} = 4 {x}^{2} - 4 \sqrt{3}x + 3$

g)

$(x + \sqrt{7} )^{2} = {x}^{2} + 2 \sqrt{7} x + 7$

h)

$(2x + 2 \sqrt{3} )^{2} = 4 {x}^{2} + 4 \sqrt{3} x + 12$

i)

$( \sqrt{3} x - \sqrt{2} )^{2} = 3 {x}^{2} - 2 \sqrt{6} x + 2$

j)

$( \sqrt{2} x + \sqrt{5} )^{2} = 2 {x}^{2} + 2 \sqrt{10} x + 5$

k)

$(2x - \sqrt{5} )^{2} = 4 {x}^{2} - 4 \sqrt{5}x + 5$

l)

$(3x - \sqrt{2} )^{2} = 9 {x}^{2} - 6 \sqrt{2}x + 2$