Question

50+2x21+4x[5+40:(19+3xb)]=116 pls

Answer 1

RĂSPUNS:

50+2×21+4×[5+40:(19+3×b)]=116

42+4×[5+40:(19+3×b)]=116-50

42+4×[5+40:(19+3×b)]=66

4×[5+40:(19+3×b)]=66-42

4×(5+40:(19+3×b)]=24

[5+40:(19+3×b)]=24:4

[5+40:(19+3×b)]=6

[40 (19+3×b)]=6-5

[40:(19+3×b)]=1

19+3×b=1×40

19+3×b=40

3×b=40-19

3×b=21

b=21:3

b=7

SPER SA FIE BINE!!!!!!!!!!!!!!