Question

5tg³$\frac{ \pi }{4} -2ctg \frac{ \pi }{6} +sin2 \pi$

Answer 1

 tgπ/4=1
sin2π=0
ctgπ/6=√3
5$5tg^3 \frac{ \pi }{4}-2ctg \frac{ \pi }{6} +sin2 \pi = [tex]5-2 \sqrt{3}$