Question

7^14+2*7^13+7^12=patrat perfect.multumesc mult.

Answer 1

(7^7+7^6)^2 = (7^7)^2 +2*7^7*7^6 +(7^6)^2=7^14 +2*7^13 +7^12

- este patrat perfect

Answer 2

$\it 7^{14}+2\cdot7^{13}+7^{12}= 7^{12}(7^2+2\cdot7+1)=7^{12}\cdot64=(7^6)^2\cdot8^2=(7^6\cdot8)^2$