Question

a) 12/13•[1/3+1:(1/7+6/7•1/6):7/6]
b) 6•[1/4+(7/36-1/24):7/6]
Va rog ajutați-ma dau coroana!

Answer 1

$\bold{a)} \ \frac{12}{13} \cdot [ \frac{1}{3} +1:( \frac{1}{7} + \frac{6}{7} \cdot \frac{1}{6} ): \frac{7}{6} ]=\frac{12}{13} \cdot [ \frac{1}{3} +1:( \frac{1}{7} + \frac{1}{7} ): \frac{7}{6} ] = \\ =\frac{12}{13} \cdot [ \frac{1}{3} +1: \frac{2}{7} : \frac{7}{6} ] =\frac{12}{13} \cdot [ \frac{1}{3} +\frac{7}{2} \cdot \frac{6}{7} ] =\frac{12}{13} \cdot [ \frac{1}{3} +\frac{6}{2} ]=\\ = \frac{12}{13}\cdot \frac{10}{3} = \frac{120}{39} = \boxed{\frac{40}{13} };$
$\bold{b)} \ 6 \cdot [ \frac{1}{4} +( \frac{7}{36} - \frac{1}{24} ): \frac{7}{6} ]=6 \cdot [ \frac{1}{4} + \frac{11}{72} \cdot \frac{6}{7} ]= 6 \cdot(\frac{1}{4}+ \frac{11}{84} )= \\ = \frac{6}{4} + \frac{66}{84} = \frac{126+66}{84} = \frac{192}{84} = \frac{48}{21} = \boxed{\frac{16}{7} }$