Question

a )  ( 2 +  2 ) ori 3 ) ori  {  2 ori 2 la puterea 2 ori 2 la puterea 43 -  2 la puterea  46 + [ 3 la puterea 148 : 3 la puterea 43 - ( 3 la puterea 5 ) la puterea 21 ]  + 16 }
b ) 122 + 12 ori { 183 : [ ( 2 ori 3 la puterea 2 ori  5 la puterea 3 ) la puterea 4 : ( 2 la puterea 4 ori 3 la puterea 7 ori  5 la puterea 12 ) + ( 2 la puterea 8 ) la puterea 9 : 2 la puterea 72 - 1 la puterea 27 ori 5 la puterea 0 ] - 9 ori ( 54 - 2 la puterea 4 ori 3 ) } 

Va rog sa ma ajutati :(((((((

Answer 1

Răspuns

A) 128

B) 206

Explicație pas cu pas

Rezolvare punctul A

(2+2×3) ×{2 ×2^2×2^43-2^46+[3^148:3 ^43-(3^5)^21]+16}=

(2+6)×{2 ^(1+2+43)-2^46+[3^(148-43)-3^(5×21)]+16}=

8 ×[2^46-2^46 +3^105 - 3^105)+16 =

8 ×16

128

Rezolvare punctul B

122 +12×{183:[(2×3^2 ×5^3)^4:(2^4×3^7×5^12)+(2^8)^9:2^72-1^27×5^0]-9×(54-2^4×3)]}=

122+12×{183:[2^4×(3^2) ^4×(5^3)^4:(2^4×3^7×5^12)+2^(8×9):2^72-1×1]-9×(54-16×3)]}=

122+12×{183:[(2^4×3^8×5^12):(2^4×3^7×5^12)+2^72:2^72-1]-9×(54-48)]}=

122+12×{183:[2^4:2^4×3^8:3^7×5^12:5^12+2^(72-72)-1]-9×6]}=

122 +12×{183:[(2^(4-4)×3^(8-7)×5^(12-12)+2^0-1]-54}=

122+12×[183:(2^0×3^1×5^0+1-1)-54]=

122 +12×[183 :(1×3×1+1-1)-54]=

122 +12×(183 :(3 +1-1)-54]=

122 +12×(183 :3-54)=

122 +12 ×(61 - 54)=

122 +12 ×7 =

122 +84 =

206