Question

A= (25 la puterea 3 ) totul la 9 : ( 4 la puterea 2 +3 la puterea 2)totul la 26 - (2017la 0 + 0 la 2017 +1la 2017)totul la 4=

Answer 1

$\it A=(25^3)^9:[(4^2+3^2)]^{26}-(2017^0+0^{2017}+1^{2017})^4=25^{27}:25^{26}-\\ \\-(1+0+1)^4=25-16=9$