Question

a= ( √3 - 1) (√6 +2) si b= (√3 +1) (√6-2)
Calculati media geometrica... va multumesc

Answer 1

$a=( \sqrt{3} -1)( \sqrt{6} +2) \\ b=( \sqrt{3} +1)( \sqrt{6} -2) \\ m_g= \sqrt{( \sqrt{3} -1)( \sqrt{6} +2)( \sqrt{3} -1)( \sqrt{6} -2)} = \sqrt{3-1+6-4} = \sqrt{4} =2$