Question

Scrie folosind o singură putere: (49/9) la puterea a doua ÷ {[5,(4)] la puterea a patra} la puterea a cincea

(75/19) la puterea a treia × (38/25) la puterea a treia

(0,12) la puterea a şaptea × (8 integi 1/3) la puterea a şaptea.

Answer 1

(49/9)² ÷ {[5,(4)]⁴}⁵ =
5,(4)=(54-5)/9=49/9=(7/3)²
=(7/3)⁴: {[(7/3)²]⁴}⁵=
=(7/3)⁴: (7/3)⁴⁰=
=(7/3)⁴ × (3/7)⁴⁰=
=(7/3)⁻³⁶=
=1/(7/3)³⁶=
=(3/7)³⁶

(75/19)³ × (38/25)³ =
=(3*5²/19)³ × (2*19/5²)³ =
=3³*5⁶/19³ × 2³*19³/5⁶ =
=(3*2)³ 

(0,12)⁷ × (8 intregi 1/3)⁷ =
=(12/100)⁷ × (25/3)⁷=
=(3/25)⁷ × (5²/3)⁷=
=3⁷/5¹⁴ × 5¹⁴/3⁷=
=1