Question

a+b+c+d = 5

{a;b;c;d} <=> invers proporționale {1/2;1/3;0,4;0,2}

a;b;c;d = ?

Answer 1

{a,b,c,d} i.p {1/2,1/3,2/5,1/5}

a/2 = b/3 = c/5/2 = d/5 = k asadar vom nota:

a= 2k, b= 3k, c= 5k/2, d= 5k

Stim ca a+b+c+d = 5

2k + 3k + 5k/2 + 5k = 5

10k + 5k/2 = 5 (amplifici cu 2 pe 10k

20k/2 + 5k/2 = 5

25k = 10

k = 10/25 = 2/5

Aflam necunoscutele

a= 2×2/5 = 4/5

b= 3×2/5 = 6/5

c= 5×2/5×1/2 = 1

d= 5×2/5 = 2