Question

Aflati inaltimile triunghiului cu laturile de 16 cm ,14cm .6 cm

Answer 1

$S= \sqrt{p(p-a)(p-b)(p-c)}$
fie a=16, b=14, c=6
$p= \frac{a+b+c}{2} => p= \frac{16+14+6}{2} =18$
p-a=18-16=2
p-b=18-14=4
p-c=18-6=12
$S= \sqrt{18*2*4*12} =24 \sqrt{3}$
$S= \frac{h*b}{2}$
$h= \frac{2S}{b}$
$h1= \frac{2*24 \sqrt{2} }{16} = 3 \sqrt{3}$
$h2= \frac{48 \sqrt{3} }{14} = \frac{24 \sqrt{3} }{7}$
$h3= \frac{48 \sqrt{3} }{6} =8 \sqrt{3}$