Question

aflati numerele naturale x si y astfel in cat urmatoarele fracti sa formeze un sir de fracti echivalernte
24\36
12\x+2
y+1\6

Answer 1

[tex] \frac{24}{36}= \frac{12}{x+2} [/tex]
12*36=24*(x+2)
432=24x+48
432-48=24x
384=24x
384/24=x
x=16
24/36=12/(16+2)

$\frac{12}{18}= \frac{y+1}{6}$
12*6=18*(y+1)
72=18y+18
72-18=18y, 54=18y, 54/18=y, y=3
12/18=(3+1)/6
$\frac{24}{36}= \frac{12}{18}= \frac{4}{6}$
x=16, y=3