Question

Ajuta-mă plss !! Am nevoie repede de răspuns :(

Answer 1

$a)a+(b+c)=(a+b)+c= 3/\frac{3}{5} + \frac{4}{15} = \frac{9+4}{15} = \frac{13}{15} \\ b)(x+y)+z=x+y+z=x+(y+z)= 2/\frac{3}{7} + \frac{17}{14} = \frac{6+17}{14} = \frac{23}{14} \\ c)x+(y+z)+t=x+y+z+t= \frac{17}{47}+ \frac{30}{47}= \frac{47}{47}=1$

Answer 2

a. 3/5+4/15=9/14+4/15=13/15;
b. 3/7+17/14=6/14+17/14=23/14;
c. 17/47+30/47=47/47=1;