Question

ajutați-mă va rog !!!​

Answer 1

Răspuns:

$-\frac{2}{3\sqrt{3}}$

Explicație pas cu pas:

$\frac{-\frac{1}{\sqrt{2}}}{\left(\sqrt{6}-\frac{\sqrt{3}}{\sqrt{2}}\right)^3}$ =$\frac{-\frac{1}{\sqrt{2}}}{\frac{3\sqrt{3}}{2\sqrt{2}}}$

$\frac{\frac{1}{\sqrt{2}}}{\frac{3\sqrt{3}}{2\sqrt{2}}}=\frac{1\cdot \:2\sqrt{2}}{\sqrt{2}\cdot \:3\sqrt{3}}$

$-\frac{1\cdot \:2\sqrt{2}}{\sqrt{2}\cdot \:3\sqrt{3}}$ = $-\frac{2}{3\sqrt{3}}$

Answer 2

raționalizăm numitorii

[(2√12-√18)/12+(2√28-√49×2)/28-

-(√63+√49×3)/21]:(²√6-√6/2)³=

[(4√3-3√2)/12+³(4√7-7√2)/28-

-⁴(3√7+7√3)/21]:(√6/2)³=

[(4√3-3√2)/12+(12√7-21√2-12√7-28√3)/84]:

(6√6/8)=

[(4√3-3√2)/12-(21√2+28√3)/84]:3√6/4=

[(4√3-3√2)/12-7(3√2+4√3)/84]×4/3√6=

[(4√3-3√2-3√2-4√3)/12]×4√6/18=

(-6√2/12)×2√6/9=(-√2/2)×(2√6)/9=

-√12/9=2√3/9