Question

Ajutatima va rog Dau Coroana​
ecuati

Answer 1

$x + \frac{2}{3} = \frac{4}{9}$

$\frac{9x}{9}+ \frac{6}{9} = \frac{4}{9}$

$9x + 6 = 4$

$9 x = 4 - 6$

$9x = -2$

$x = -\frac{2}{9}$

$x + \frac{3}{4} = \frac{11}{12}$

$\frac{12x}{12} + \frac{9}{12} = \frac{11}{12}$

$12x + 9 = 11$

$12x = 11 - 9$

$12x = 2$

$x = \frac{2}{12}$

$x=\frac{1}{6}$

$-2x + 3 = -1\frac{1}{2}$

$-2x + 3 = -\frac{1}{2}$

$\frac{-4x}{2} + \frac{6}{2} = -\frac{1}{2}$

$-4x + 6 = -1$

$-4x = -1 - 6$

$-4x = -7$

$x = \frac{7}{4}$

$12,3 - x = 0,84$

$-x =- 12,3 + 0,84$

$-x = -11.46 | \cdot (-1)$

$x=11.46$