Question

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Answer 1

$\dfrac{x}{y} = 0,4 \iff \dfrac{x}{y} = \dfrac{4^{(2} }{10} = \dfrac{2}{5} \iff x = \dfrac{2y}{5}$

b)

$y = 2,5 = \dfrac{25^{(5} }{10} = \dfrac{5}{2}$

$x = \dfrac{\not2}{\not5} \cdot \dfrac{\not5}{\not2} = 1 \implies x = 1$

c)

$y = 1,2 = \dfrac{12^{(2} }{10} = \dfrac{6}{5}$

$x = \dfrac{2}{5} \cdot \dfrac{6}{5} \implies x = \dfrac{12}{25}$

d)

$y = 3,(3) = \dfrac{33-3}{9} = \dfrac{30^{(3} }{9} = \dfrac{10}{3}$

$x = \dfrac{2}{\not5} \cdot \dfrac{\not10}{3} \implies x = \dfrac{4}{3}$

Answer 2

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