Question

alfabetul matematic :
s) (8x9+s-5x8)-(30-5x2+5=100:2:2=
t) (36-5x6-t)+9x8-7x10=4x7:7=
u) (7x7-6x6+u)-24:3-2x10=81:9=
v) (v-5x5-2x8)+6x5-5x10=6:2=
x) (x+8x2+6x8-8x9+8x8=6x10+2x4=
y) (y+5x5)-6x6=40:2+3=
z) (6x9-z)-3x10+16:2=4x3x1=

Answer 1

s) (8x9+s-5x8)-(30-5x2+5)=100:2:2
(72+s-40)-(30-10+5)=50:2
(72+s-40)-(20+5)=25
(72+s-40)-25=25
72+s-40=25+25
72+s-40=50
72+s=50+40
72+s=90
s=90-72
s=18

t) (36-5x6-t)+9x8-7x10=4x7:7
(36-30-t)+72-70=28:7
(6-t)+72-70=4
(6-t)+72=4+70
(6-t)+72=74
6-t=74-72
6-t=2
t=6-2
t=4

u) (7x7-6x6+u)-24:3-2x10=81:9
(12+u)-8-20=9
(12+u)-8=9+20
(12+u)-8=29
12+u=29+8
12+u=37
u=37-12
u=25

v) (v-5x5-2x8)+6x5-5x10=6:2
(v-25-16)+30-50=3
(v-25-16)+30=3+50
(v-25-16)+30=53
v-25-16=53-30
v-25-16=23
v-25=23+16
v-25=39
v=39+25
v=64

x) (x+8x2+6x8-8x9+8x8)=6x10+2x4
(x+16+48-72+64)=60+8
x+16+48-72+64=68
x+16+48-72=68-64
x+16+48-72=4
x+16+48=4+72
x+16+48=76
x+16=76-48
x+16=32
x=32-16
x=16

y) (y+5x5)-6x6=40:2+3
(y+25)-36=20+3
(y+25)-36=23
y+25=23+36
y+25=59
y=59-25
y=34

z) (6x9-z)-3x10+16:2=4x3x1
(54-z)-30+8=12x1
(54-z)-30+8=12
(54-z)-30=12-8
(54-z)-30=4
54-z=4+30
54-z=34
z=54-34
z=20

Dacă tu crezi că merit, astept coroana!