Matematică, întrebare adresată de olgacaraman25, 8 ani în urmă

alo
Calculaţi:
a) 5/2 +9/2 – 2/5;
b) 3×7/2 -4/2;
c) 3×4/8 +2×9/2;
d) (3/3 - 6):2 t
e) (12/2 - 11/2): 1/20
f) 5/1(13/2 + 4/3);​

Răspunsuri la întrebare

Răspuns de Matei
8

Salut.

Punctul a)

\displaystyle{  \frac{5}{2}+\frac{9}{2} - \frac{2}{5} = \frac{5 + 9}{2} - \frac{2}{5}   }

\displaystyle{   =\frac{14}{2}-\frac{2}{5}  }

\displaystyle{    =7 - \frac{2}{5} = ^{5)}\frac{7}{1}-\frac{2}{5} }

\displaystyle{   = \frac{35}{5}-\frac{2}{5}=\frac{35-2}{5}  }

\boxed{=\frac{33}{5}}

Punctul b)

\displaystyle{  3 \cdot \frac{7}{2}-\frac{4}{2}=\frac{3 \cdot 7}{2} - \frac{4}{2}  }

\displaystyle{  =\frac{21}{2}-\frac{4}{2}=\frac{21-4}{2}   }

\boxed{=\frac{17}{2}}

Punctul c)

\displaystyle{ 3 \cdot \frac{4}{8} + 2 \cdot \frac{9}{2}=\frac{3 \cdot 4}{8} + \frac{2 \cdot 9}{2}    }

\displaystyle{  =\frac{12}{8}^{(4}+\frac{18}{2}   }

\displaystyle{ =\frac{3}{2} + \frac{18}{2} =\frac{3+18}{2}    }

\boxed{=\frac{21}{2}}

Punctul d)

\displaystyle{(\frac{3}{3} - 6) : 2= (1 - 6) : 2     }

\displaystyle{ = (-5) : 2    }

\boxed{=-2,5}

Punctul e)

\displaystyle{  (\frac{12}{2} -\frac{11}{2}) : \frac{1}{20}=\frac{12-11}{2} : \frac{1}{20}   }

\displaystyle{ =\frac{1}{2} : \frac{1}{20} = \frac{1}{2} \cdot \frac{20}{1}    }

\displaystyle{   =\frac{20}{2}  }

\boxed{=10}

Punctul f)

\displaystyle{  \frac{5}{1} \cdot (^{3)}\frac{13}{2} + ^{2)}\frac{4}{3}) = 5 \cdot (\frac{39}{6}+\frac{8}{6})   }

\displaystyle{   = 5 \cdot \frac{39+8}{6}  }

\displaystyle{   =5 \cdot \frac{47}{6}  }

\boxed{=\frac{235}{6}}

- Lumberjack25

Alte întrebări interesante