Matematică, întrebare adresată de GicuFranaru, 9 ani în urmă

Am mare nevoie de ajutor doua exerciti ma puteti ajuta? dau multe puncte si coroana.

Anexe:

Răspunsuri la întrebare

Răspuns de Trombolistul
1

9) \\  \\ a) \frac{2}{4} +  \frac{5}{10} +  \frac{3}{6} =  \frac{1}{2} +  \frac{1}{2} +  \frac{1}{2} =  \frac{1 + 1 + 1}{2} =  \frac{3}{2} = 1 \frac{1}{2} \\  \\ b) \frac{4}{8} +  \frac{9}{24} +  \frac{15}{36} =  \frac{1}{2} +  \frac{3}{8} +  \frac{5}{12} =  \frac{1 \times 12}{2 \times 12} +  \frac{3 \times 3}{8 \times 3} +  \frac{5 \times 2}{12 \times 2} =  \frac{12}{24} +  \frac{9}{24} +  \frac{10}{24} =  \frac{12 + 9 + 10}{24} =  \frac{31}{24} = 1 \frac{7}{24} \\  \\ c) \frac{7}{33} +  \frac{16}{44} =  \frac{7}{3} +  \frac{4}{11} =  \frac{7}{33} +  \frac{4 \times 3}{11 \times 3} =  \frac{7}{33} +  \frac{12}{33} =  \frac{7 + 12}{33} =  \frac{19}{33} \\  \\ d) \frac{9}{30} +  \frac{28}{20} +  \frac{20}{40} =  \frac{3}{10} +  \frac{7}{5} +  \frac{1}{2} =  \frac{3}{10} +  \frac{7 \times 2}{5 \times 2} +  \frac{1 \times 5}{2 \times 5} =  \frac{3}{10} +  \frac{14}{10} +  \frac{5}{10} =  \frac{3 + 14 + 5}{10} =  \frac{22}{10} =  \frac{11}{5} = 2 \frac{1}{5} \\  \\ e) \frac{1}{3} +  \frac{20}{30} +  \frac{44}{33} +  \frac{95}{57} =  \frac{1}{3} +  \frac{2}{3} +  \frac{4}{3} +  \frac{5}{3} =  \frac{1 + 2 + 4 + 5}{3} =  \frac{12}{3} = 4 \\  \\ f) \frac{231}{175} +  \frac{231231}{175175} =  \frac{33}{25} +  \frac{33}{25} =  \frac{33 + 33}{25} =  \frac{66}{25} = 2 \frac{16}{25} \\  \\ 10) \\  \\ a) \frac{24}{25} +  \frac{1}{4} +  \frac{7}{100} =  \frac{24 \times 4}{25 \times 4} +  \frac{1 \times 25}{4 \times 25} +  \frac{7}{100} =  \frac{96}{100} +  \frac{25}{100} +  \frac{7}{100} =  \frac{96 + 25 + 7}{100} =  \frac{128}{100} =  \frac{32}{25} = 1 \frac{7}{25} \\  \\ b) \frac{9}{20} +  \frac{1}{180} +  \frac{7}{60} +  \frac{11}{30} =  \frac{9 \times 9}{20 \times 9} +  \frac{1}{180} +  \frac{7 \times 3}{60 \times 3} +  \frac{11 \times 6}{30 \times 6} =  \frac{81}{180} +  \frac{1}{180} +  \frac{21}{180} +  \frac{66}{180} =  \frac{81 + 1 + 21 + 66}{180} =  \frac{169}{180} \\  \\ c) \frac{11}{45} +  \frac{13}{15} +  \frac{1}{3} =  \frac{11}{45} +  \frac{13 \times 3}{15 \times 3} +  \frac{1 \times 15}{3 \times 15} =  \frac{11}{45} +  \frac{39}{45} +  \frac{15}{45} =  \frac{11 + 39 + 15}{45} =  \frac{65}{45} =  \frac{13}{9} = 1 \frac{4}{9} \\  \\ d)5 +  \frac{7}{20} +  \frac{13}{20} = 5 +  \frac{7 + 13}{20} = 5 + 1 = 6 \\  \\ e)( \frac{7}{24} +  \frac{1}{8}) + ( \frac{7}{9} +  \frac{13}{18}) =  \frac{10}{24} +  \frac{7}{9} +  \frac{13}{18} =  \frac{5}{12} +  \frac{7}{9} +  \frac{13}{18} =  \frac{69}{36} =  \frac{23}{12} \\  \\ f) \frac{3}{44} +  \frac{9}{11} +  \frac{3}{2} =  \frac{3}{44} +  \frac{9 \times 4}{11 \times 4} +  \frac{3 \times 22}{2 \times 22} =  \frac{3}{44} +  \frac{36}{44} +  \frac{66}{44} =  \frac{3 + 36 + 66}{44} =  \frac{105}{44} = 2 \frac{17}{44}

GicuFranaru: Multumesc
GicuFranaru: da nu se vede rezultatele la unele
GicuFranaru: a gata am vazut acm
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