Question

Am nevoie de niste răspunsuri aici!!!

Answer 1

4. 4x²-4xy+y²+x²+4xy+4y² = 5x²+5y² = 5(x²+y²) 5. a) 4xyz(5y+4x-6z) b) (x+y)(4+5-10) = (x+y)*(-1) = -x-y 6. Inlocuim 5 + 5² + 5^3 = 5 + 25 + 125 = 155

Answer 2

4)

(2x-y)²+(x+2y)²=

((2x)²+2•2x(-y)+(-y)²)+(x²+2x•2y+(2y)²)=

(2²•x²-2•2xy+y²)+(x²+2•2xy+2²•y²)=

(4x²-4xy+y²)+(x²+4xy+4y²)=

4x²-4xy+y²+x²+4xy+4y=

4x²+x²-4xy+4xy+y²+4y²=

5x²+5y²

$5) \\ \\ 20xy ^{2}z + 16 {x}^{2}yz - 24 {xyz}^{2} = 4xyz( \frac{20 {xy}^{2}z }{4xyz} + \frac{ {16x}^{2}yz }{4xyz} + \frac{ - 24 {xyz}^{2} }{4xyz} = 4xyz(5y + 4x - 6z)$

$4(x + y) + 5(x + y) - 10(x + y) = - (x + y) = - x - y$