Question

Am nevoie urgenta de rezultate,❤️​

Answer 1

ABCD este trapez isoscel ⇒ AD = BC = 10 cm

a)

P (ABCD) = AB+BC+CD+AD = 24+10+8+10 = 52 cm

b)

$AM = \dfrac{AB - CD}{2} = \dfrac{24 - 8}{2} = \dfrac{16}{2} = 8 \ cm$

$AN = \dfrac{AB}{2} = \dfrac{24}{2} = 12 \ cm$

T.Pitagora în ΔAMD:

DM² = AD²-AM² = 10²-8² = 36 = 6²

⇒ DM = 6 cm

AB || CD ⇒ ΔAMD~ΔANE

$\dfrac{AM}{AN} = \dfrac{DM}{NE} \iff \dfrac{8}{12} = \dfrac{6}{NE}$

$NE = \dfrac{12 \cdot 6}{8} = \dfrac{72}{8} \implies \bf NE = 9 \ cm$

q.e.d.