Question

Avem triunghiul ABC , m<) A = 90 de grade , AB=6 cm , AC= 3 cm , Aflati sin C = ?

Answer 1

 [tex]\Rightarrow\;\;BC=\sqrt{6^2+3^2}=\sqrt{45}=3\sqrt5\;;\\ sin\widehat{C}=\frac{6^{(3}}{3\sqrt5}=\frac{2}{\sqrt5}=\frac{2\sqrt5}{5}[/tex]