Question

Calculand tg60°-2·sin60°, se obtine?....

Answer 1

[tex]tg 60^o = \sqrt{3} . \\ sin 60^o= \frac{ \sqrt{3} }{2} =\ \textgreater \ 2 *sin 60^o = \frac{ \sqrt{3} }{2} * 2 = \sqrt{3} \\ tg 60^o - 2 *sin 60^o = \sqrt{3} - \sqrt{3} \\ \boxed{tg 60^o - 2 *sin 60^o = 0. } \\ -Mayu-[/tex]