Question

calculați 18*9^2 pe 3^12

Answer 1

$\dfrac{18\cdot 9^2}{3^{12}} =\dfrac{2\cdot9\cdot9^2}{3^{2\cdot6}}=\dfrac{2\cdot9^3}{9^6}=\dfrac{2\cdot9^3}{ 9^3\cdot9^3}=\dfrac{2}{9^3}=\dfrac{2}{729}$